1In [81]: df.groupby('Column1')['Column3'].apply(list).to_dict()
2Out[81]: {0: [1], 1: [2, 3, 5], 2: [1, 2], 3: [4, 5], 4: [1], 5: [1, 2, 3]}
3
1In [433]: {k: list(v) for k, v in df.groupby('Column1')['Column3']}
2Out[433]: {0: [1], 1: [2, 3, 5], 2: [1, 2], 3: [4, 5], 4: [1], 5: [1, 2, 3]}
3