count number of words in a string

Solutions on MaxInterview for count number of words in a string by the best coders in the world

showing results for - "count number of words in a string"
Nicole
09 Jan 2018
1public static void main (String[] args) {
2
3     System.out.println("Simple Java Word Count Program");
4
5     String str1 = "Today is Holdiay Day";
6
7     String[] wordArray = str1.trim().split("\\s+");
8     int wordCount = wordArray.length;
9
10     System.out.println("Word count is = " + wordCount);
11}
12
Angelo
20 Jun 2019
1 String name = "Carmen is a fantastic play"; //arbitrary sentence
2        
3        int numWords = (name.split("\\s+")).length; //split string based on whitespace
4                                                //split returns array - find legth of array
5        
6        System.out.println(numWords);
Sofia
01 May 2020
1  String str = "I am happy and why not
2  and why are you not happy and you should be";
3        String [] arr = str.split(" ");
4        Map<String, Integer> map = new HashMap<>();
5
6        for (int i=0 ; i < arr.length ; i++){
7                if (!map.containsKey(arr[i])){
8                    map.put(arr[i],1);
9                } else{
10                    map.put(arr[i],map.get(arr[i])+1);
11                }
12        }
13        for(Map.Entry<String, Integer> each : map.entrySet()){
14
15  System.out.println(each.getKey()+" occures " + each.getValue() + " times");
16        }
Esteban
23 Jan 2018
1public static void main(String[] args)
2    { 
3        //Scanner object instantiation 
4        Scanner dude = new Scanner(System.in); 
5       
6       //variable declaration 
7       String string1 = ""; 
8       int count = 0; 
9       boolean isWord = false; 
10       
11       
12       //user prompt and input 
13       System.out.println("Enter in your string"); 
14       string1 = dude.nextLine(); 
15       
16       int endOfLine = string1.length()-1; 
17       char ch [] = string1.toCharArray(); 
18       
19       for (int i = 0; i < string1.length(); i++)
20       { 
21           if(Character.isLetter(ch[i]) && i != endOfLine)
22           {//if character is letter and not end of line
23               isWord = true; //it is part of a word 
24           }  
25           if (!Character.isLetter(ch[i]) && isWord)
26           { //if character is not a letter, and previous 
27             //character is a letter i.e. non-letter is 
28             //preceded by character 
29              count++; //add to word count 
30              isWord = false; //get ready to detect new word  
31           }
32           if (Character.isLetter(ch[i]) && i == endOfLine)
33           { //if character is letter 
34             //and at end of line 
35               count++; //add to word count 
36               isWord = false; 
37           }
38           
39       } 
40       System.out.println("There are " +count+ " words");     
41    }
Lorenzo
13 Mar 2016
1// Count words (text separated by whitespace) in a piece of text
2use std::collections::HashMap;
3
4fn word_count(text: &str) -> HashMap<&str, i32> {
5    let mut map = HashMap::new();
6    for word in text.split_whitespace() {
7        *map.entry(word).or_insert(0) += 1;
8    }
9    map
10}
11
12fn main() {
13    println!("Count of words = {:?} ",word_count("the quick brown fox jumped over the lazy dog"));
14}
Mads
23 Oct 2019
1 public static int count(String word) {
2    if (word == null || word.isEmpty()) {
3      return 0;
4    }
5
6    int wordCount = 0;
7
8    boolean isWord = false;
9    int endOfLine = word.length() - 1;
10    char[] characters = word.toCharArray();
11
12    for (int i = 0; i < characters.length; i++) {
13
14      // if the char is a letter, word = true.
15      if (Character.isLetter(characters[i]) && i != endOfLine) {
16        isWord = true;
17
18        // if char isn't a letter and there have been letters before,
19        // counter goes up.
20      } else if (!Character.isLetter(characters[i]) && isWord) {
21        wordCount++;
22        isWord = false;
23
24        // last word of String; if it doesn't end with a non letter, it
25        // wouldn't count without this.
26      } else if (Character.isLetter(characters[i]) && i == endOfLine) {
27        wordCount++;
28      }
29    }
30
31    return wordCount;
32  }
33
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