convert np shape 28a 2c 29 to 28a 2c1 29

1# numpy array/vector (n,) dimension -> (n,1) dimension conversion
2a  = np.arange(3)         # a.shape  = (3,)
3b  = a.reshape((3,1))     # b.shape  = (3,1)
4c  = b.reshape((3,))      # c.shape  = (3,)
5
6c2 = b.reshape((-1,1))    # c2.shape = (3,)

1'''
2This code is contributed by :
3Tanishq Vyas (github : https://github.com/tanishqvyas )
4'''
5
6actual = actual.reshape((actual.shape[0], 1))