check if string has special characters java

1 //1. Using Regex
2
3import java.util.regex.Matcher; 
4import java.util.regex.Pattern;
5
6public class JavaHungry {
7    public static void main(String args[]) {
8        String inputString = "Alive*is*Awesome$";
9        Pattern pattern = Pattern.compile("[^a-zA-Z0-9]");
10        Matcher matcher = pattern.matcher(inputString);
11        boolean isStringContainsSpecialCharacter = matcher.find();
12        if(isStringContainsSpecialCharacter)
13            System.out.println(inputString+ " contains special character");
14        else    
15            System.out.println(inputString+ " does NOT contain special character");
16    }
17}
18
19//Output:
20//Alive*is*Awesome$ contains special character
21
22
23//2. Without Using Regex 
24
25public class JavaHungry {
26    public static void main(String args[]) {
27        String inputString = "Alive*is*Awesome$";
28        String specialCharactersString = "!@#$%&*()'+,-./:;<=>?[]^_`{|}";
29        for (int i=0; i < inputString.length() ; i++)
30        {
31            char ch = inputString.charAt(i);
32            if(specialCharactersString.contains(Character.toString(ch))) {
33                System.out.println(inputString+ " contains special character");
34                break;
35            }    
36            else if(i == inputString.length()-1)     
37                System.out.println(inputString+ " does NOT contain special character");
38        }
39    }
40}