check if even or odd javascript

1function isEven(n) {
2   return n % 2 == 0;
3}
4
5function isOdd(n) {
6   return Math.abs(n % 2) == 1;
7}

1function evenOrOdd(num) { //for string length take string
2  if (num % 2 == 0) {//and replace numm with string.length here
3    return "even";
4  } else {
5    return "odd";
6  }
7}

1for(let count =0; count<=100;count++){
2 count%2==0? console.log(`${count} is even`):console.log(`${count} is odd`);
3 ;
4}

1function solution(num) {
2    return num % 2 === 0 ? 'Even' : 'Odd'
3}
4
5

1let isEven = (n) => !(n&1);