Please place your php code into another file called api.php and use $.ajax to get these data with JSON format. To convert data into JSON format data you should use json_encode() php function.
I have set sample example you can see here.
Please refer below code example:
api.php
$arrLabels = array("January","February","March","April","May","June","July");
$arrDatasets = array('label' => "My First dataset",'fillColor' => "rgba(220,220,220,0.2)", 'strokeColor' => "rgba(220,220,220,1)", 'pointColor' => "rgba(220,220,220,1)", 'pointStrokeColor' => "#fff", 'pointHighlightFill' => "#fff", 'pointHighlightStroke' => "rgba(220,220,220,1)", 'data' => array('28', '48', '40', '19', '86', '27', '90'));
$arrReturn = array(array('labels' => $arrLabels, 'datasets' => $arrDatasets));
print (json_encode($arrReturn));
example.html
$.ajax({
type: 'POST',
url: 'api.php',
success: function (data) {
lineChartData = data;
var myLine = new Chart(document.getElementById("canvas").getContext("2d")).Line(lineChartData);
var ctx = document.getElementById("canvas").getContext("2d");
window.myLine = new Chart(ctx).Line(lineChartData, {responsive: true});
}
});
Please note that you should pass value of randomScalingFactor() at api.php.
Please check and let me know if you require any further help.