c 2b 2b evaluate expression

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Elicia
10 Sep 2016
1#include "tinyexpr.h"
2#include <stdio.h>
3
4int main()
5{
6    double answer = te_interp("3*2+4*1+(4+9)*6", 0);
7    printf("Answer is %f\n", answer);
8    return 0;
9}
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