armstrong numbers problem java

1// Java program to print all armstrong numbers between given range
2import java.util.Scanner;
3public class ArmstrongNumbersGivenRange 
4{
5   public static void main(String[] args) 
6   {
7      int number, startNumber, endNumber, a, rem, n, count = 0;
8      Scanner sc = new Scanner(System.in);
9      System.out.println("Please enter starting number range: ");
10      startNumber = sc.nextInt();
11      System.out.println("Please enter ending number range: ");
12      endNumber = sc.nextInt();
13      for(a = startNumber + 1; a < endNumber; a++)
14      {
15         n = a;
16         number = 0;
17         while(n != 0)
18         {
19            rem = n % 10;
20            number = number + rem * rem * rem;
21            n = n / 10;
22         }
23         if(a == number)
24         {
25            if(count == 0)
26            {
27               System.out.println("Armstrong numbers between given range " + startNumber + " and " + endNumber + ": ");
28            }
29            System.out.print(a + "  ");
30            count++;
31         }
32      }
33      // if there is no Armstrong number found between range
34      if(count == 0)
35      {
36         System.out.println("Sorry!! There's no armstrong number between given range " + startNumber + " and " + endNumber);
37      }
38      sc.close();
39   }
40}

1// 4 digit armstrong number in java
2public class ArmstrongNumberDemo
3{
4   public static void main(String[] args) 
5   {
6      int num = 9474, realNumber, remainder, output = 0, a = 0;
7      realNumber = num;
8      for(;realNumber != 0; realNumber /= 10, ++a);
9      realNumber = num;
10      for(;realNumber != 0; realNumber /= 10)
11      {
12         remainder = realNumber % 10;
13         output += Math.pow(remainder, a);
14      }
15      if(output == num)
16      {
17         System.out.println(num + " is an Armstrong number.");
18      }
19      else
20      {
21         System.out.println(num + " is not an Armstrong number.");
22      }
23   }
24}

1 int c=0,a,temp;  
2    int n=153;//It is the number to check armstrong  
3    temp=n;  
4    while(n>0)  
5    {  
6    a=n%10;  
7    n=n/10;  
8    c=c+(a*a*a);  
9    }  
10    if(temp==c)  
11    System.out.println("armstrong number");   
12    else  
13        System.out.println("Not armstrong number");   

1import java.util.Scanner;
2
3/*
4 *@author: Mayank Manoj Raicha
5 * Armstrong Number in Java: A positive number is called armstrong number if it is equal to the sum of cubes of its digits 
6 * for example 0, 1, 153, 370, 371, 407 etc.
7 * 153 = (1*1*1)+(5*5*5)+(3*3*3)  = 1+125+27 = 153
8 */
9public class ArmstrongNumberExample {
10
11	public static void main(String[] args) {
12		
13		int sum = 0;
14		
15		Scanner in = new Scanner(System.in);
16		System.out.println("Enter the number: ");
17		int input = in.nextInt(); //1634
18		String val = String.valueOf(input);
19		char[] charArray = val.toCharArray();  //charArray[0] = "1" , charArray[1] = "6", charArray[2] = "3", charArray[3] = "4"
20		int[] numArray = new int[charArray.length]; //Declaring this array to store the result of getPowerOfNumber() method for each digit.
21		
22		//for each char element calculate the power of number and store it in the "cubedNumArray" array.
23		for(int i=0; i<charArray.length; i++) {
24			numArray[i] = getPowerOfNumber(Integer.parseInt(String.valueOf(charArray[i])), charArray.length);
25			sum = sum + numArray[i];
26		}
27		
28      //Compare if the resulting sum is equal to the original input.
29		if(sum == input) {
30			System.out.println("Entered number is an Armstrong number.");
31		}else {
32			System.out.println("Entered number is NOT an Armstrong number.");
33		}
34		
35		in.close();
36	}
37
38  	//Calculate & Return the value of the first argument raised to the power of the second argument
39	public static int getPowerOfNumber(int num, int count) {
40		return (int) Math.pow(num, count);
41	}
42}